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[几何] 轨迹

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hjfmhh posted 2017-1-6 23:23 |Read mode
轨迹.png

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caesarxiu posted 2017-1-6 23:43
用向量解。先以A为原点构建直角坐标系,设AB和BC边的向量并表示出其坐标,由面积关系可得|AB|*|BC|=1,原点指向中点的向量就可以表示出来,然后坐标转移就好了。

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色k posted 2017-1-7 01:14
QQ截图20170107005126.png

因 AE*AF 为定值,即 D 点在坐标系中为双曲线 $xy=k$,变回直角坐标系就是作一个切变变换,不会改变曲线类型,所以还是双曲线。
这名字我喜欢

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