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[函数] 存在最小值求参数范围

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isee posted 2017-2-24 16:42 |Read mode
Last edited by isee 2017-2-24 17:59若$f(x)=\sin ^3x+a\cos^2x$在$(0,\pi)$上存在最小值,则实数$a$的取值范围是________.

还没弄明白二阶导数如何如何。。。。。先搁这里。。。。

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realnumber posted 2017-2-24 20:14
Last edited by realnumber 2017-2-24 20:24$\sin{x}=t,0<t<1,f(x)=t^3+a(1-t^2)=g(t)$
存在最小值就是,存在$0<x<\pi$,有$f(x)\le f(0)=f(\pi)$=a,.
即存在$0<t\le 1$,有$t^3+a(1-t^2)\le a$,即$t\le a$,所以a>0

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original poster isee posted 2017-2-24 21:01
学习了!


不知道用高等数学中的二阶导数是否能解决。

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乌贼 posted 2017-2-24 23:11
回复 2# realnumber
换元思想,学习

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