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[函数] 一个指对不等式

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qinxianming82 posted 2017-4-1 14:12 |Read mode
Last edited by qinxianming82 2017-4-1 14:39$xlnx-\frac{1}{e^x}>-1-\frac{3}{e^3}$(来源于光子问答)
请各位高手有空看看!

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original poster qinxianming82 posted 2017-4-1 18:20
请论坛上的高手赐教

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original poster qinxianming82 posted 2017-4-2 10:50
我参看了光子问答中的指对混合不等式的证明方法,也没思路!

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陈习晖 posted 2017-4-2 16:26
xlnx-1/e^x>-1-2/e^2

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游客 posted 2017-4-6 10:29
未命名.PNG


最后一行的取值得换一个。

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