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[数列] 又一个数列不等式问题

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realnumber posted 2017-4-20 19:03 |Read mode
QQ图片20170419211138cxaa.png
$S_n$是数列{$a_n$}的前n项和,就第3问
我的解答是先猜得$1>a_n>1-\frac{1}{n+1}$或$1>a_n>1-\frac{1}{\sqrt{2n}}$,数学归纳法证明。
但群里问问题的还是觉得可能有别的更自然的解法.

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