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[几何] 找个平几解法(理应是陈题)——有了

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isee Posted 2017-7-7 15:09 |Read mode
Last edited by isee 2017-7-7 15:41解析的话,设直线硬求交点,计算向量的点积。

题如下:

直线$l$过点$A(1,0)$交圆$H:(x-3)^2+(y-4)^2=4$于$B,C$两点,交另一条直线$l':x+2y+3=0$于点$G$.
若$BC$的中点为$D$.
求证:$AD\cdot AG=8.$
c-l.png

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 Author| isee Posted 2017-7-7 15:16
Last edited by isee 2017-7-7 15:31目前知道的是$l'$是与(点A关于圆H的)极线平行。

嗯解决了,一个相似就OK了。
c-l.png

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kuing Posted 2017-7-7 15:37
这么简单,这帖是不是可以扔掉了

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 Author| isee Posted 2017-7-7 15:40
Last edited by isee 2017-7-7 16:18回复 3# kuing


    如果不是发现和点$A$的极线平行,有得一算。。。

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