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[不等式] 指对再来一发

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v6mm131 posted 2017-7-18 11:37 |Read mode

$(x-1)e^x-\ln x>-\frac{1}{2}$

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original poster v6mm131 posted 2017-7-18 13:51

$(x-1)e^x-x^2\ge-1>\ln x-x^2-\frac{1}{2}$

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2025-7-15 14:55 GMT+8

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