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[不等式] 样子还不错的对数不等式

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v6mm131 posted 2017-7-18 11:45 |Read mode
证明:$\ln x+x+\frac{1}{x}>\frac{3}{2}$

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original poster v6mm131 posted 2017-7-18 14:05
Last edited by v6mm131 2017-7-18 14:12带换一波先,令$x=e^t$ 则原不等式可化为:
\[t+e^t+e^{-t}>\frac{3}{2}\]
熟知:$e^x+e^{-x}\ge2+x^2$ 则要证的不等式显然成立

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original poster v6mm131 posted 2017-7-18 14:27
也可以这么估计$ \ln x+\frac{1}{x}\ge\frac{5x^2-2x+3}{2x^2+4x}>\frac{9}{5}-\frac{27x}{25}$

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