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[不等式] 根式不等式一条

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v6mm131 Posted 2017-7-25 00:37 |Read mode

若$0 \le a \le b\le c,a+b+c=3$求证：\[\sqrt{3a^2+1}+\sqrt{5a^2+3b^2+1}+\sqrt{7a^2+5b^2+3c^2+1}\le 9\]

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Author| v6mm131 Posted 2017-7-27 17:01

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