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[不等式] 三元不等式一条

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v6mm131 posted 2017-8-7 01:14 |Read mode

若$a,b,c \ge 0$,且满足$a^2+3b^2+7c^2=11$,证明：\[2b+6c+abc\leqslant 9 \]

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2025-6-8 18:59 GMT+8

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