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[函数] 除了一个根之外,其余根的绝对值都小于1

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isee posted 2017-9-15 16:26 |Read mode
证明:$$nx^n=1+x+x^2+\cdots+x^{n-1}$$的根除了一个根之外,其余根的绝对值都小于1.

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kuing posted 2017-9-15 17:05
显然 $x=1$ 是根,$x=-1$ 不是根;
若 $x>1$ 则 $x^n>1$, $x^n>x$, \ldots, $x^n>x^{n-1}$,等式显然不成立;
若 $x<-1$,当 $n$ 为偶数时同上,当 $n$ 为奇数时上述全部不等号反向,等式亦不成立。
即得证。

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original poster isee posted 2017-9-15 17:11
回复 2# kuing

果然还是不等式……又秒一个...

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