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[不等式] 请教一道不等式

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25717246 Posted 2017-10-15 00:09 |Read mode
已知$a,b>0,\frac{32}{a^3}+\frac{8}{b^2}=1$,则$a+b$的最小值为

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kuing Posted 2017-10-15 01:31
已知$a,b>0,\frac{32}{a^3}+\frac{8}{b^2}=1$,则$a+b$的最小值为
25717246 发表于 2017-10-15 00:09
检查下是否抄错题,按目前的数据来说此题属于“扔掉型高次方程”

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 Author| 25717246 Posted 2017-10-15 21:18
回复 2# kuing 没看到原题,是从朋友那得来的一道题

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kuing Posted 2017-10-15 21:59
回复 3# 25717246

那就扔掉好了

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 Author| 25717246 Posted 2017-10-15 22:38
回复 4# kuing OK

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