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[函数] 萌题一枚

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realnumber Posted 2018-1-31 14:18 |Read mode
函数$y=(a\cos^2{x}-3)\sin{x}$的最小值为-3,则a的取值范围是 ( )
A[-1.5,+∞)B(-∞,-1.5]C[-2,12]D[-1.5,12]
















令$t=\sin{x} \in[-1,1]$
$a(1-t^2)t\ge 3t-3$,化简为$a(1+t)t\ge -3$

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kuing Posted 2018-1-31 16:46
标题黨……

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isee Posted 2018-1-31 21:08

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 Author| realnumber Posted 2018-1-31 21:24
回复 2# kuing
一开始搞得很复杂,导数处理,

    kk萌题大概什么样?

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zhcosin Posted 2018-2-1 14:30
何萌之有呀?

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 Author| realnumber Posted 2018-2-1 18:19
我也解释不了,现在看来坐实了 标题党

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