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[数列] Fibonacci

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guanmo1 posted 2018-2-28 22:12 |Read mode

斐波那契数列.png

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kuing posted 2018-2-28 22:23

这么简单
\[
a_{5n+5}=a_{5n+4}+a_{5n+3}=2a_{5n+3}+a_{5n+2}=3a_{5n+2}+2a_{5n+1}=5a_{5n+1}+3a_{5n}
\]
即得证。

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zhcosin posted 2018-2-28 22:31

回复 2# kuing

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其妙 posted 2018-3-3 10:20

能搞一个能被8整除的么

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2025-7-15 15:24 GMT+8

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