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[函数] 2018年北京卷理科第8题 线性规划

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isee posted 2018-6-7 22:14 |Read mode
Last edited by hbghlyj 2025-5-3 21:54北京卷还真爱考这个,线性规划如此就谢幕了

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没画,答案不确定。

(8)设集合$A=\{(x,y)|x-y\ge 1,ax+y>4,x-ay\le 2\},$则
(A)对任意实数$a$,$(2,1)\in A$                                (B)对任意实数$a$,(2,1)$\notin A$
(C)当且仅当$a<0$时,(2,1)$\notin A$                        (D)当且仅当$a\le \frac 32$时,(2,1)$\notin A$

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kuing posted 2018-6-8 22:10
这个根本不用画图啊,四个选项都只是关于一个具体的点在不在集合中,那就直接代入好了啊,`(2,1)\in A\iff 2a+1>4\land 2-a\le2\iff a>3/2`,所以显然就是 D 了,又一送分题……

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original poster isee posted 2018-6-8 22:15
看看今年单科数学均分会上升多少

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敬畏数学 posted 2018-6-10 13:10
此题很搞笑的。玩得是哪曲啊。貌似是文学题。

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