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数据也不怪,总体还算平稳简单的一张,浙江卷

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realnumber Posted 2018-6-8 07:59 |Read mode
Last edited by realnumber 2018-6-8 09:47 QQ截图20180608074451bbb.png
5.D,奇函数,x=$\frac{\pi}{2}$,代入,总是初中的描点法,或说解析几何的“点在曲线上,坐标满足方程,反之亦然”
7.D,p=0,0.5,1代入,数据由集中→分散→集中变化,
8.点E无限接近B点,就B点好了(你说不能与B重合,就不代了?得有叛逆想法,说错了 ,得创新,不拘泥于成见)
9.A,$(\vv{b}-\vv{e})·(\vv{b}-3\vv{e})=0$,画圆吧
10.B,由$\ln{x}\le x-1$等,可得公比q,-1<q<0
CBCBD
ADDAB

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 Author| realnumber Posted 2018-6-8 08:14
Last edited by realnumber 2018-6-8 10:04 QQ截图20180608081611CCC.png
11.x=8,y=11
12.-2,8
13.$\frac{\sqrt{21}}{7},3$
14.7
15.(1,4),1<λ≤3或λ>4
16.1260
17.m=5,令$t^2=m,t>1$,$A(2t\cos β,t\sin β),B(2t\cos α,t\sin α),$
由$\vv{AP}=2\vv{PB}$,消去β得到$4\sin α=t+\frac{3}{t}$,得到$1<t\le 3$
所以B点纵坐标为$t\sin α=\frac{t^2+3}{4}$,横坐标绝对值为$\abs{2t\cos α}=\sqrt{4t^2-(\frac{t^2+3}{2})^2}=\frac{\sqrt{-t^4+10t^2-9}}{2}$,在$t^2=5$时取到最大,最大为2.
18.(1)$\frac{4}{5},$(2)$\frac{16}{65}$或$-\frac{56}{65}$
已经看到有人发微信答案了,不用做了
19.以A为坐标原点,以AA'为z轴,面ABC为xoy平面,AC'为x轴建立空间直角坐标系
$\frac{\sqrt{39}}{13}$
20.q=2,$b_n=15-\frac{4n+3}{2^{n-2}}$
21.$[6\sqrt{2},\frac{15\sqrt{10}}{4} ]$

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isee Posted 2018-6-8 22:55
相对 江苏浙江上海,反而比全国I,II,III难一些,最易是北京卷,未见天津卷。

18年高考真题基本都可以上新课直接拿来用,当时就消化了

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