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[几何] 两个正方形套在一起,证三角形全等

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郝酒 posted 2018-7-20 19:19 |Read mode
如图,ABCD,A'B'C'D'是两个正方形,三角形AEF全等于三角形BGH,
求证三角形CJK全等于三角形DMN。
正方形证全等.jpg


感觉没有什么好办法,只有解析法暴算了,求助下。

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kuing posted 2018-7-20 20:15
QQ截图20180720201307.png
易证 两红色线长之和 = 两蓝色线长之和,所以……

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original poster 郝酒 posted 2018-7-20 20:52
原来如此,多谢ku版,
给出红色线长=蓝色线长的一种证法:)

正方形证全等.jpg

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