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请教一道求积题目

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数学小黄 Posted at 2013-10-29 09:37:33 |Read mode
Last edited by hbghlyj at 2025-4-7 09:14:09\[\prod_{i=0}^{\infty}(1+\frac{1}{2^{2^i}})\]

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战巡 Posted at 2013-10-29 10:11:32
回复 1# 数学小黄


挺简单的吧.........
\[\prod_{i=0}^{n}(1+\frac{1}{2^{2^i}})=2·(1-\frac{1}{2})(1+\frac{1}{2})(1+\frac{1}{2^2})...(1+\frac{1}{2^{2^n}})\]
\[=2(1-\frac{1}{2^2})(1+\frac{1}{2^2})(1+\frac{1}{2^4})...(1+\frac{1}{2^{2^n}})\]
\[=2(1-\frac{1}{2^{2^{n+1}}})\]
取极限就有
\[\prod_{i=0}^{\infty}(1+\frac{1}{2^{2^i}})=2\]

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 Author| 数学小黄 Posted at 2013-10-29 10:43:44
回复 2# 战巡

谢谢谢谢

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kuing Posted at 2013-10-29 12:19:28
初中的连锁反应题……

手机版Mobile version|Leisure Math Forum

2025-4-21 14:24 GMT+8

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