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[不等式] 求最小值

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lemondian posted 2018-10-3 11:07 |Read mode
求$\dfrac{a}{\sin x}+\dfrac{b}{\cos x},0<x<\dfrac{\pi}{2}$的最小值。

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色k posted 2018-10-3 13:18
一、你写漏了 a,b>0
二、用权方和(或 holder)秒杀
三、当然,最直接的求导也可以

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dahool posted 2018-10-3 23:02
回复 2# 色k

holder会做,权方和怎么处理呢?对权方和紧紧是知道,不会用

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Infinity posted 2018-10-6 21:16
回复 3# dahool

凑指数即可:
分母$\sin x=\sqrt{\sin^2x}$,$\cos x=\sqrt{1-\sin^2 x}$.
分子$a=(a^{2/3})^{3/2}$,$b=(b^{2/3})^{3/2}$
于是最小值为$(a^{2/3}+b^{2/3})^{\frac 32}$

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