Forgot password?
 Register account
View 1336|Reply 4

[数列] 数列通项

[Copy link]

9

Threads

17

Posts

134

Credits

Credits
134

Show all posts

大一新生 Posted 2019-1-6 15:55 |Read mode
数列$\{a_n\}_{-\infty}^{+\infty}$每$10$个数字循环一次,当$n=1,2,\cdots,10$时,$a_n=n$.
求数列$\{a_n\}_{-\infty}^{+\infty}$的通项公式.(我用$mod$没写出来...)

686

Threads

110K

Posts

910K

Credits

Credits
91229
QQ

Show all posts

kuing Posted 2019-1-6 16:22
每10个数字循环一次就是指周期为10是吗?如果是的话那就是 `a_n=(n-1)\bmod 10+1` 呗

9

Threads

17

Posts

134

Credits

Credits
134

Show all posts

 Author| 大一新生 Posted 2019-1-6 19:15
回复 2# kuing
k版主,怎么写才能让下标为0和负整数时也适用哇?

9

Threads

17

Posts

134

Credits

Credits
134

Show all posts

 Author| 大一新生 Posted 2019-1-6 19:24
不用分段的形式写似乎很难...

686

Threads

110K

Posts

910K

Credits

Credits
91229
QQ

Show all posts

kuing Posted 2019-1-6 19:29
回复 3# 大一新生

2# 的通项也适用于0和负数啊,`(-1)\bmod10=9` 啊

Mobile version|Discuz Math Forum

2025-5-31 11:15 GMT+8

Powered by Discuz!

× Quick Reply To Top Edit