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[函数] 一个函数的单调性问题

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无言 posted 2019-3-18 15:30 |Read mode
图像 1.png

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色k posted 2019-3-18 15:37
两边之差啊,这还用解释吗?这里第三边与 x 轴平行,所以右边越远越接近第三边,当然是增,左边则是负的第三边,也一样。

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kuing posted 2019-3-18 17:56
这样吧:
QQ截图20190318175512.png
显然 `PA+QB<PB+QA`,即 `PA-PB<QA-QB`,所以递增。这够简单了吧

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original poster 无言 posted 2019-3-18 18:49
回复 2# 色k

说了像没说一样哈!

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original poster 无言 posted 2019-3-18 18:52
回复 3# kuing


    为什么是显然的呢?

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kuing posted 2019-3-18 19:14
回复 5# 无言

我那个擦啊,一点平几感觉都没有了吗?
设 PB、QA 的交点是 X,则 PA<XA+XP,QB<XB+XQ,相加就是了……

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original poster 无言 posted 2019-3-18 19:46
回复 6# kuing

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original poster 无言 posted 2019-3-18 19:47
回复 6# kuing

ok

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