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lrh2006 Posted 2019-4-19 23:25 |Read mode
再向大家请教一题 微信图片_20190419231637.jpg

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业余的业余 Posted 2019-4-20 05:10
$\vv{OP}=\lambda\vv{OA}+\mu\vv{OB}=\lambda(\vv{OA}-\vv{OB})+2\vv{OB}=\lambda\vv{BA}+2\vv{OB}$

显然当 $\lambda\to-\infty$ 时,$\vv{OP}$ 的极限状态是 $-\vv{BA}=\vv{AB}$, 当 $\lambda\to\infty$ 时,$\vv{OP}$ 的极限状态是 $\vv{BA}$, 显然  $OP$ 与 $OA$ 的夹角 $\theta\in[0,\frac {2\pi}3)$, 故投影的取值范围为 $(-1,2]$

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敬畏数学 Posted 2019-4-20 16:56
P轨迹在一条直线上,投影就可以直接从图中获得。

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