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[不等式] 高考模拟题求助

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longzaifei posted 2019-5-27 11:27 |Read mode
题目:某码头有总重量为$13.5$吨的一批货箱,对于每个货箱重量都不超过$0.35$吨的任何情况,都要一次运走这批货箱,则至少要准备载重$1.5$吨的卡车_______辆

我会解决货箱重量都是一样的情况,如果这批货箱的重量不都是一样的,没有思路!

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爪机专用 posted 2019-5-27 12:30
我连题目都读不懂

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isee posted 2019-5-27 12:42
Last edited by isee 2019-5-27 12:53回复 1# longzaifei


看不懂题,请问,如果这批货箱就只有10吨和3.5吨两个,如何运走?无法运?



如果13吨+0.3吨+0.2吨,一张车,只运走0.3,0.2?

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original poster longzaifei posted 2019-5-27 13:28
回复 3# isee

每个货箱的重量都不超过0.35吨
原题如上,我一个字都没改!

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realnumber posted 2019-5-27 19:11
回复  longzaifei


看不懂题,请问,如果这批货箱就只有10吨和3.5吨两个,如何运走?无法运?



如果13 ...
isee 发表于 2019-5-27 12:42
13就超过0.35了

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realnumber posted 2019-5-27 19:31
比如38只箱子都是0.35吨+0.2吨一只,合计13.5吨
但一辆汽车只能装4只,因此这样情况下需要10辆车.
又比如42只箱子每只都是0.32吨+0.06吨一只,合计13.5吨
一辆汽车只能装4只,此时需要11辆车.
最浪费的情况,猜一个[13.5/(1.5-0.35)]+1=12辆

比如44只0.301吨箱子+0.256吨一只
一辆汽车只能装4只,此时需要12辆车.

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original poster longzaifei posted 2019-5-28 11:22
回复 6# realnumber

$1.5-4\times0.301=0.296>0.256 $
11辆车还是可以的

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isee posted 2019-5-28 23:38
回复 7# longzaifei


这么说,11辆是这题的答案了?

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original poster longzaifei posted 2019-5-29 13:25
回复 8# isee

答案是11辆,但是怎么证明呢?

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