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[不等式] 一道三元不等式

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hbghlyj Posted 2019-7-24 23:35 |Read mode
设$a, b, c \geq 0, \quad a+b+c=2$,求证$a^{2} b^{2}+b^{2} c^{2}+c^{2} a^{2} \leq 1$
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kuing Posted 2019-7-25 00:22
与《撸题集》P.632 题目 5.1.22 是等价的。

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 Author| hbghlyj Posted 2019-7-25 10:37
回复 2# kuing
看来我做对了。原题是<=2,不能取等。我做得<=1。这里真是交流大大小小疑难问题的好去处。

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