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[函数] 复合函数有解求参数范围

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走走看看 posted 2019-7-31 07:37 |Read mode
已知函数f(x)=log2(x+1),x>1,f(x)=x-1,x≤1        ,若关于x的方程f[f(x)]=a有解,则实数a的取值范围是___.

zybang.com/question/8c8d68435fff11a837ac22e150274fee.html

不太理解f(x)=t有解得出的a的范围。

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original poster 走走看看 posted 2019-7-31 13:27
回复 1# 走走看看


    知道了,把值域当成定义域即可。

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