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[函数] 求解函数解析式

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沉香陈香 Posted 2013-11-2 20:50 |Read mode

如题

如题

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其妙 Posted 2013-11-2 23:20

建议改为$f(x)+f(\dfrac{x+2016}{x-1})=x$，可以不？

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转化与化归

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转化与化归 Posted 2013-11-4 20:30

回复 2# 其妙

改了以后无解

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其妙 Posted 2013-11-4 22:50

回复 3# 转化与化归
那改为$f(x)+2f(\dfrac{x+2016}{x-1})=x$，有没有解？
另：楼主的怎么解？

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