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[函数] 求解函数解析式

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沉香陈香 Posted at 2013-11-2 20:50:20 |Read mode

如题

如题
如题

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其妙 Posted at 2013-11-2 23:20:09
建议改为$f(x)+f(\dfrac{x+2016}{x-1})=x$,可以不?

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转化与化归 Posted at 2013-11-4 20:30:29
回复 2# 其妙




改了以后无解

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其妙 Posted at 2013-11-4 22:50:53
回复 3# 转化与化归
那改为$f(x)+2f(\dfrac{x+2016}{x-1})=x$,有没有解?
另:楼主的怎么解?

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2025-4-21 14:24 GMT+8

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