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[几何] 到平行四边形四点距离成比例的轨迹为一条等轴双曲线

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hbghlyj Posted at 2019-8-22 17:23:51 |Read mode
Last edited by hbghlyj at 2024-12-30 20:40:00设四边形ABCD是平行四边形,则使得PA·PC=PB·PD成立的点P轨迹为一条等轴双曲线,其中心与平行四边形的中心重合,其对称轴与过ABCD的等轴双曲线的对称轴成45角。
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谢谢科普,辛苦大佬。  Posted at 2024-12-31 09:38

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 Author| hbghlyj Posted at 2021-4-25 01:08:13

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 Author| hbghlyj Posted at 2024-12-31 04:26:41
发到MSE问一问。

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这是啥网站?大佬见识真广,可惜我们大多数人对歪国洋文是睁眼瞎啊。  Posted at 2024-12-31 09:40

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2025-4-22 06:37 GMT+8

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