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[不等式] 二元最值

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Shiki Posted 2019-8-29 20:03 |Read mode
$x,y>0$,$x^2+y^2+\frac{1}{x}+\frac{1}{y}=\frac{27}{4}$求$\frac{15}{x}-\frac{3}{4y}$的最小值。
= =

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kuing Posted 2019-8-29 20:07

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 Author| Shiki Posted 2019-8-29 20:11
回复 2# kuing
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