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[函数] 求$\arcsin(\sin 2019^\circ)$

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isee Posted 2019-8-31 15:59 |Read mode
求$\arcsin(\sin 2019^\circ)$

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realnumber Posted 2019-8-31 16:11
$\sin 2019^\circ=-\sin 39^\circ$
$- 39^\circ=-\frac{13\pi}{60}$答案就这个?

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 Author| isee Posted 2019-8-31 17:14
回复 2# realnumber


是啊,太简单了,不相信,是吧。

用得太少了。

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hbghlyj Posted 2023-1-10 19:22
\[\arcsin(\sin(x))=\left| x-2 \pi  \left\lfloor \frac{x}{2 \pi }+\frac{3}{4}\right\rfloor +\frac{\pi }{2}\right| -\frac{\pi }{2}\]

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