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[不等式] 中秋快乐！整式不等式

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力工 posted 2019-9-13 21:21 |Read mode

已知$a,b,c\geqslant 0,a^2+b^2+c^2+abc=4$,求证： $\Sigma a(b+3)\geqslant 6(abc+1)$.

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2025-7-23 09:47 GMT+8

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