$\tan A\cos B\sin C$的最值

hbghlyj · 2020-1-27 16:40

Last edited by hbghlyj 2020-2-5 00:06(1)在锐角△ABC中,$ma^2+2ab\cos C=nb^2$,$\tan A\cos B\sin C$的最小值为M,当m,n取任意正数时,求M的取值范围
(2)在锐角△ABC中,$\cos C=n\left(\frac ba-\frac ab\right)$,$\tan A\cos B\sin C$的最小值为M(n),求$\mathop {\lim }\limits_{n \to 0} M(n)$

hbghlyj · 2020-2-5 00:03

(2)$\frac{\sqrt2}2$

facebooker · 2020-2-8 10:39

第一题咋弄啊？

dvkxgl · 2020-3-19 00:10

怎么弄呀大佬

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[函数] $\tan A\cos B\sin C$的最值