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[几何] 证明四点共圆

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Shiki posted 2020-2-12 07:18 |Read mode
Last edited by hbghlyj 2025-5-6 02:53已知 $M$ 为 $\triangle A B C$ 的边 $A C$ 的中点,$P, ~ Q$分别为线段 $A M$ , $C M$ 上的点,且满足 $A C=2 P Q$ . $\triangle A B Q$ 的外接圆与边 $B C$ 交于另一点 $X, \triangle B C P$ 的外接圆与边 $A B$交于另一点 $Y$ .证明:$B, ~ X, ~ M, ~ Y$ 四点共圆.
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乌贼 posted 2020-2-12 13:20
颜色相同的三角形相似,先蓝后绿。
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