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[几何] 循环相切圆 尺规作图题

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hbghlyj Posted 2020-3-21 23:05 |Read mode
Last edited by hbghlyj 2020-3-22 14:54正方形ABCD,DEFG的中心重合,AB与DE的夹角为$\alpha,\alpha\in(0,\frac\pi2)$,求AP:PB并判断点P能否尺规作出

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 Author| hbghlyj Posted 2020-3-21 23:13
Last edited by hbghlyj 2020-3-22 07:46 几何2020.3.21.jpg
由AB+DE=AP+PD+BQ+QE=AP+PD+AR+RD,求作圆外切四边形APDR可转化为:
几何2020.3.21.jpg
给定常数c和点P,求作两点A,B,点A在y轴上,点B在x轴上,OA+BP=OB+PA=c

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