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用MMA求三角形的三个角度

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青青子衿 posted 2020-4-5 12:11 |Read mode
Last edited by 青青子衿 2020-4-22 16:11(Function[{a, b, c},
     ArcCos[(a^2 + b^2 - c^2)/(2 a*b)]/Degree // DMSString] @@@
    Partition[#, 3, 1, 1]) & /@ {{5, 9, 7}, {4, 3, 6}, {5, 6, 7}}

(Function[{a, b, c},
     ArcCos[(a^2 + b^2 - c^2)/(2 a*b)]/Pi*180 // DMSString] @@@
    Partition[#, 3, 1, 1]) & /@ {{5, 9, 7}, {4, 3, 6}, {120, 192, 168}}

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