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[几何] 数量积最大值

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chudengshuxue Posted 2020-4-8 21:12 |Read mode
微信图片_20200408211041.png

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kuing Posted 2020-4-8 21:48
就是 $2\vv{AM}\cdot\vv{MP}$,所以当 $OP\px AM$ 时最大

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 Author| chudengshuxue Posted 2020-4-8 21:57
回复 2# kuing


    为毛是OP∥AM时最大呢?

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hbghlyj Posted 2020-4-8 22:06
回复 3# chudengshuxue
作切线

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hbghlyj Posted 2020-4-8 22:08
回复 2# kuing
这样说是$4\sqrt{10}-8$?

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 Author| chudengshuxue Posted 2020-4-8 22:09
回复 4# hbghlyj


    ???

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kuing Posted 2020-4-9 01:13
回复 3# chudengshuxue

…………要 MP 在直线 AM 上的投影最长啊……就是 P 处的切线与 AM 垂直啊……也就是 OP // AM 啊…………

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敬畏数学 Posted 2020-4-9 10:58
Last edited by 敬畏数学 2020-4-9 12:02$ \vv{AM} (\vv{BP}+\vv{CP})=2\vv{AM}\cdot \vv{MP}=2\vv{AM}\cdot (\vv{MO}+\vv{OP})=2\vv{AM}\cdot \vv{MO}+2\vv{AM}\cdot \vv{OP}\leqslant -8+4\sqrt{10}$,等号成立当$ OP\px AM $

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 Author| chudengshuxue Posted 2020-4-9 11:50
回复 8# 敬畏数学

计算结果错了。不过不影响思路。或者BP=BO+OP,CP=CO+OP,展开后,发现只需要算AM.OP,其它都是定值。这样,取等条件更明确,看到AM∥OP。

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 Author| chudengshuxue Posted 2020-4-9 11:50
回复 7# kuing


    是的,是的。后来发现了。之前竟然没注意到AM长为定值

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 Author| chudengshuxue Posted 2020-4-9 11:52
要想快速计算的话,注意到除了P点在动,其它都是定值,所以坐标化之后,用参数方程,转化为三角函数最值更快。最小值也能出来。

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敬畏数学 Posted 2020-4-9 12:03
回复 9# chudengshuxue 感谢指正!半径误认为是1,2.已经纠正。

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 Author| chudengshuxue Posted 2020-4-9 20:48
回复 12# 敬畏数学

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