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[不等式] 2020年天津卷第14题 条件不等式

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isee posted 2020-7-17 22:43 |Read mode
已知$a>0,b>0$,且$ab=1$,则$\frac 1{2a}+\frac 1{2b}+\frac 8{a+b}$的最小值为_________.

2020年天津卷第14题


难得有个偶一眼能看到用均值不等式的,丢上来~

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色k posted 2020-7-17 22:55
这题的唯一作用就是坑那些想都不想直接令a=b的人

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