Discuz Math Forum»Forum › Mathematics › High School › 一道不等式小菜

Return to list New

View 1149|Reply 1

[不等式] 一道不等式小菜

[Copy link]

107 Threads	224 Posts	1 Reputation

Send PM

facebooker posted 2021-1-26 17:55 |Read mode

pro:$\sqrt{x^{2}-1}+\sqrt{x-1}\leqslant x\sqrt{x}$

Reply Edit 0

673 Threads	110K Posts	218 Reputation

Send PM

kuing posted 2021-1-26 20:19

懒得想，直接平方移项再平方，最后分解为 `x^2(x^2-x-1)^2\geqslant0`，看来取等和黄金分割有关……

Reply Edit

Return to list New

Quick Reply

× Quick Reply To Top Edit

2025-7-15 15:25 GMT+8

Powered by Discuz!

Processed in 0.011601 seconds, 22 queries