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[几何] 等边$\triangle ABC$的的重心的轨迹方程

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lemondian posted 2021-5-11 08:20 |Read mode
Last edited by lemondian 2021-5-11 10:03设等边$\triangle ABC$的边长为2,顶点$A$在$x$轴的正半轴上滑动,顶点$B$在$y$轴的正半轴上滑动,求$\triangle ABC$的重心$G$的轨迹方程。

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色k posted 2021-5-11 09:38
你题打错了

anyway,这是老掉牙的问题了,一般情况下轨迹为椭圆,见:matrix67.com/blog/archives/2896

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original poster lemondian posted 2021-5-11 10:04
回复 2# 色k
不好意思,改过来了

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