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[不等式] 含绝对值的最大最小值问题

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力工 Posted 2021-5-15 09:29 |Read mode
已知$a$为实数,若存在$x∈[1,2]$使$max\{|x+\frac{a}{x}|,|x+\frac{a}{x}+2|\}\geqslant 5$,求$a$的范围.

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hbghlyj Posted 2021-5-15 12:48
考虑问题的反面:$\forall x\in[1,2],\abs{x+\frac ax}<5\wedge\abs{x+\frac ax+2}<5$.
$\forall x\in[1,2],x+\frac ax<3\Leftrightarrow a<x(3-x)\Leftrightarrow a<2$.
$\forall x\in[1,2],x+\frac ax>-5\Leftrightarrow a>-x(x+5)\Leftrightarrow a>-6$.
所以a的范围是$a\in(-6,2)$.
原题答案就是$a\in(-\infty,-6]\cup[2,+\infty)$.

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