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[函数] 一眼看尽`f(2021)`

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isee posted 2021-7-28 20:00 |Read mode
定义在`\mathrm R`上的偶函数`f(x)`满足`f(x+2)=-f(x)`,则`f(2021)=`_______.

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力工 posted 2021-7-28 22:16
回复 1# isee
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其妙 posted 2021-8-3 17:40
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$f(x)=\cos\dfrac{\pi}2x$符合要求,故$f(2021)=\cos\dfrac{2021\pi}2=0$,
或者$f(x)=0$也符合要求。
妙不可言,不明其妙,不着一字,各释其妙!

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