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[不等式] 求助一个不等式

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lemondian Posted 2021-8-17 01:14 |Read mode
已知$a,b>0,a+b\leqslant 1,k\leqslant 6$,求证:$(\frac{1}{a}+\frac{1}{b^2}-k)(\frac{1}{a^2}+\frac{1}{b}-k)\geqslant (6-k)^2$

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yao4015 Posted 2021-8-17 13:32
有反例: $(a,b,k)=[2/3,1/3,6]$

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kuing Posted 2021-8-17 14:26
改为 `k\le33/7` 即可。

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isee Posted 2021-8-19 13:30
回复 3# kuing


主楼命题粗用柯西不等式以乎很对,但"="取不到。

继而k的上界如何求?

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