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[数论] 完全平方数

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chudengshuxue posted 2022-3-16 08:54 |Read mode

Last edited by hbghlyj 2025-3-19 17:30$a, b \inZ_+,(a b+1) \mid\left(a^2+b^2\right)$，求证：$\frac{a^2+b^2}{a b+1}$ 为完全平方数.

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Tesla35 posted 2022-3-16 10:00

1988第29届IMO

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isee posted 2022-3-16 10:03

29th IMO 1988

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