Forgot password?
 Register account
View 256|Reply 0

sin(f(x))积分不等式

[Copy link]

3158

Threads

7933

Posts

45

Reputation

Show all posts

hbghlyj posted 2022-3-25 16:56 |Read mode
设f′′(x)在[a,b]上连续且非零,设f′(x)≥m>0, ∀x∈[a,b],证明:$$\left|\int _a^b \sin(f(x))\,dx\right|\leq \frac{4}{m}$$

证明(MSE)
存在 c∈(a,b):
\begin{align*}
  \abs{\int_a^b \sin f(x) \, dx}
  &= \abs{\int_a^b f'(x)\sin f(x) \cdot \frac 1{f'(x)}\, dx}\\
  &\le \frac 1{f'(a)}\abs{\int_a^c f'(x)\sin f(x)\, dx} + \frac 1{f'(b)}\abs{\int_c^b f'(x)\sin f(x)\, dx}\\
  &\le \frac 1m \abs{\int_{f(a)}^{f(c)} \sin u \, du} + \frac 1m
\abs{\int_{f(c)}^{f(b)}\sin u\, du}
\end{align*}设$\beta = \alpha + 2k\pi + \gamma$, $γ<2π$, $k∈\Bbb N$\begin{align*}
  \abs{\int_\alpha^\beta \sin u \, du}
   &= \abs{\int_0^{\gamma}\sin u \, du}\\
   &\le \int_0^{\pi} \abs{\sin u}\, du\\
   &= 2.
\end{align*}代入上面的不等式即证.

Quick Reply

Advanced Mode
B Color Image Link Quote Code Smilies
You have to log in before you can reply Login | 快速注册

$\LaTeX$ formula tutorial

Mobile version

2025-6-8 06:44 GMT+8

Powered by Discuz!

Processed in 0.031064 second(s), 21 queries

× Quick Reply To Top Edit