Forgot password?
 Register account
View 269|Reply 1

Prove a graph is not planar

[Copy link]

3159

Threads

7941

Posts

610K

Credits

Credits
63770
QQ

Show all posts

hbghlyj Posted 2022-4-15 10:41 |Read mode
dmoi Exercise 4.3.15:
Explain why we cannot use the same sort of proof we did in Exercise 4.3.14 to prove that the graph below is not planar. Then explain how you know the graph is not planar anyway.

Solution:
$v=11,e=25,g=3$, if the graph is planar, $v-e+f=2⇒f=16$. Notice that $48=gf≤2e=50$ is satisfied, so we cannot use the same sort of proof we did in Exercise 4.3.14 to prove that the graph below is not planar.
If the graph is planar, the graph in Exercise 4.3.14 is its subgraph so would be planar too, contradiction. Therefore the graph is not planar.

3159

Threads

7941

Posts

610K

Credits

Credits
63770
QQ

Show all posts

 Author| hbghlyj Posted 2022-4-15 11:12
The graph contains the following subgraph that is a subdivision of $K_5$:
Kuratowski's theorem that a graph is planar if and only if it does not contain a subgraph that is a subdivision of $K_5$ or $K_{3,3}$.

Mobile version|Discuz Math Forum

2025-5-31 10:32 GMT+8

Powered by Discuz!

× Quick Reply To Top Edit