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[几何] linear involutions

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hbghlyj Posted 2022-4-29 05:39 |Read mode
Last edited by hbghlyj 2023-5-10 20:36en.wikipedia.org/wiki/Affine_involution In Euclidean geometry, of special interest are involutions which are linear or affine transformations over the Euclidean space $\Bbb R^n$. Such involutions are easy to characterize and they can be described geometrically. Linear involutions To give a linear involution is the same as giving an involutory matrix, a square matrix $A$ such that $$A^{2}=I\tag1$$ where $I$ is the identity matrix. It is a quick check that a square matrix $D$ whose elements are all zero off the main diagonal and ±1 on the diagonal, that is, a signature matrix of the form $$D={\begin{pmatrix}\pm 1&0&\cdots &0&0\\0&\pm 1&\cdots &0&0\\\vdots &\vdots &\ddots &\vdots &\vdots \\0&0&\cdots &\pm 1&0\\0&0&\cdots &0&\pm 1\end{pmatrix}}$$ satisfies (1), i.e. is the matrix of a linear involution. It turns out that all the matrices satisfying (1) are of the form $$A=U^{ −1}DU,$$ where $U$ is invertible and $D$ is as above. That is to say, the matrix of any linear involution is of the form $D$ up to a matrix similarity. Geometrically this means that any linear involution can be obtained by taking oblique reflections against any number from 0 through $n$ hyperplanes going through the origin. (The term oblique reflection as used here includes ordinary reflections.) One can easily verify that $A$ represents a linear involution if and only if $A$ has the form $$A = ±(2P - I)$$ for a linear projection $P$. Affine involutions If $A$ represents a linear involution, then $x→A(x−b)+b$ is an affine involution. One can check that any affine involution in fact has this form. Geometrically this means that any affine involution can be obtained by taking oblique reflections against any number from 0 through $n$ hyperplanes going through a point $b$. Affine involutions can be categorized by the dimension of the affine space of fixed points; this corresponds to the number of values 1 on the diagonal of the similar matrix $D$ (see above), i.e., the dimension of the eigenspace for eigenvalue 1. The affine involutions in 3D are: • the identity • the oblique reflection in respect to a plane • the oblique reflection in respect to a line • the reflection in respect to a point. Isometric involutions In the case that the eigenspace for eigenvalue 1 is the orthogonal complement of that for eigenvalue −1, i.e., every eigenvector with eigenvalue 1 is orthogonal to every eigenvector with eigenvalue −1, such an affine involution is an isometry. The two extreme cases for which this always applies are the identity function and inversion in a point. The other involutive isometries are inversion in a line (in 2D, 3D, and up; this is in 2D a reflection, and in 3D a rotation about the line by 180°), inversion in a plane (in 3D and up; in 3D this is a reflection in a plane), inversion in a 3D space (in 3D: the identity), etc.

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TSC999 Posted 2022-4-29 08:42
这是不是相当于太阳从某个角度照在 F 形标杆上的影子?

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 Author| hbghlyj Posted 2023-5-11 03:40
Last edited by hbghlyj 2024-3-31 17:25linear projection
向量空间$V$,$P\in\operatorname{Aut}(V)$,设$$U=\operatorname{im}P,W=\ker P$$如果$$P=P^2$$则$P$称为沿着$W$到$U$上的投影
$P$的特征值满足$\lambda^2=\lambda⇒\lambda∈\{0,1\}$,故$V=U\oplus W$.
反过来,把$V$分解成直和$$V=U\oplus W$$则$P=I_U\oplus 0_W$,从而确定了$P$. (splitting lemma)
$V$分解成直和的方式不唯一,给定一个子空间$U$(地面),有很多到 $U$ 的投影(阳光沿不同的$W$照射)。如果$P$是等距变换,则$W$是$U$的正交补(阳光垂直于$U$照射),是唯一的。
Screenshot 2023-05-10 212105.png

上面的图片是用SVG+MathML制作的(用MathJax生成MathML), 矢量图比位图更容易修改.
$type image-3.svg (3.44 KB, Downloads: 44)

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 Author| hbghlyj Posted 2024-4-1 01:25
TSC999 发表于 2022-4-29 00:42
这是不是相当于太阳从某个角度照在 F 形标杆上的影子?
是啊,太阳光是平行线,平行投影,即仿射变换

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