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[函数] 函数最值问题

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lrh2006 posted 2022-5-8 19:42 |Read mode
Last edited by lrh2006 2022-5-8 19:56已知函数$f(x)=|x^2-2x-b|,x\in [-1,1]$,其中$b\in R.$ 记f(x)的最大值为g(b),则g(b)的最小值为________.
我算出来的答案是2,不知道对不对,大家怎么做这道题?

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kuing posted 2022-5-9 13:24
从图形来看 2 是对的。

f 在 [-1,1] 上要么单调,要么先减后增,取最大值一定在端点,即 g(b)=max{f(-1),f(1)}。

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original poster lrh2006 posted 2022-5-9 15:55
回复 2# kuing


    嗯嗯,我是看成$x^2-2x$与b的距离
    话说这个动图真可爱

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facebooker posted 2022-5-9 20:23
回复 1# lrh2006


    铅锤距离  对的

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original poster lrh2006 posted 2022-5-9 21:45
回复 4# facebooker


    好的,谢谢!

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