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[几何] 经过圆与锥线的四个交点的锥线的中心的轨迹是等轴双曲线

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hbghlyj posted 2022-8-12 10:09 |Read mode
C. Smith, An Elementary Treatise on Conic Sections, Macmillan, London, 1885. pp. 226 (EXAMPLES ON CHAPTER X.)

59. With a fixed point for centre any circle is described cutting a conic in four points real or imaginary; shew that the locus of the centres of all conics through these four points is a rectangular hyperbola, which is independent of the radius of the circle.

[shew: old-fashioned spelling of ‘show’.]

设圆心为$(\alpha,\beta)$, 则经过圆与锥线的四个交点的任一锥线为$$a x^{2}+b y^{2}-1-\lambda\left\{(x-\alpha)^{2}+(y-\beta)^{2}-c^{2}\right\}=0$$
求出中心的坐标并消去$\lambda$得$$b y (-x +α) + a x (y - β)=0$$ Screenshot 2022-08-12 at 02-45-21 A Proof of the Reflective Property of the Para.png

即$$xy=\frac{a \beta  x-\alpha  b y}{a-b}$$这是一条以$\left(-\frac{\alpha  b}{a-b},\frac{a \beta }{a-b}\right)$为中心且经过原点的等轴双曲线, 且与圆的半径$c$无关.
Q.E.D

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