an array of three function pointers

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在讨论区遇到这样的一道题:
What is x in the following program?

1. #include<stdio.h>
3. int main()
4. {
5.     typedef char (*(*arrfptr[3])())[10];
6.     arrfptr x;
7.     return 0;
8. }

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答案是x is an array of three function pointers
参考Return array from function in C和C - Array of pointers
讨论:

Gaurav Kumar Garg said: (Jan 19, 2014)          
typedef char (*(*arrfptr[3])())[10];

Meaning of this is

arrfptr is array of 3 function pointer which return array of 10 dimension whose type is char.
So,
x is an array of three function pointers.

如果举个例子就好了

1. #include<stdio.h>
2. typedef char(*(*arrfptr[3])())[10];
3. char arr[10];
4. char(*F())[10] { return &arr; }
5. arrfptr x = {&F,&F,&F};
6. int main() {
7.         return 0;
8. }

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运行成功,无报错
解释:
char arr[10]    ⟶    arr是10个字符的数组
char(*F())[10]    ⟶    F是函数,返回类型为“10个字符的数组”的指针
char(*(*x[3])())[10];    ⟶    x是3个“返回类型为‘10个字符的数组的指针’的函数”的指针的数组