Forgot password
 Register account
View 128|Reply 0

二项式级数 \binom反过来

[Copy link]

3226

Threads

7843

Posts

52

Reputation

Show all posts

hbghlyj posted 2022-11-27 06:18 |Read mode
\[\sum _{k=0}^{\infty } \binom{\frac{1}{2}}{k} \left(-\frac{1}{2}\right)^k=\left(1-\frac12\right)^{\frac12}\]
把 \binom 反过来:
\[\sum _{k=0}^{\infty } \binom{k}{\frac{1}{2}} \left(-\frac{1}{2}\right)^k=\frac{12+2\sqrt{3} \log \left(2- \sqrt{3}\right)}{9 \pi }\]
好像只有当$\frac12$能写成arcsinh的形式

Quick Reply

Advanced Mode
B Color Image Link Quote Code Smilies
You have to log in before you can reply Login | Register account

$\LaTeX$ formula tutorial

Mobile version

2025-7-23 10:05 GMT+8

Powered by Discuz!

Processed in 0.011943 seconds, 22 queries