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[数论] $p∈ℚ[X],p(ℤ)⊆2ℤ∪3ℤ⇒p(ℤ)⊆2ℤ∨p(ℤ)⊆3ℤ$

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hbghlyj posted 2023-1-23 01:08 |Read mode
Last edited by hbghlyj 2023-1-23 20:33

Suppose that $p ∈ ℚ[X]$ maps integers to integers and is such that for all $z∈ℤ$ either 2 divides $p(z)$ or 3 divides $p(z)$. Show that the quantifiers may be reversed i.e. that either for all $z∈ℤ$ we have 2 divides $p(z)$, or for all $z∈ℤ$ we have 3 divides $p(z)$.

设 $p ∈ ℚ[X]$ 将整数映射到整数,并且对于所有 $z∈ℤ$,$p(z)$ 是 2 或 3 的倍数。证明对于所有 $z∈ℤ$ 我们有 $p(z)$ 是 2 的倍数,或者对于所有 $z∈ℤ$ 我们有 $p(z)$ 是 3 的倍数。

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original poster hbghlyj posted 2023-1-24 02:50

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