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[几何] Douglas的五边形 拿破仑定理推广

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hbghlyj posted 2023-2-12 06:25 |Read mode
任意五边形$(p_0,p_1,p_2,p_3,p_4)$.
将每个顶点 $p_i$ 连接到 对边 $p_{i+2}p_{i+3}$ 的中点;
将该线延长其长度的 $1/\sqrt{5}$ 到点 $q_i$,则五边形 $(q_0,q_1, q_2, q_3, q_4)$ 和凸正五边形仿射等价。将该线缩短其长度的 $1/\sqrt{5}$ 到点 $r_i$,则五边形 $(r_0, r_1, r_2, r_3, r_4)$ 和正五角星仿射等价。
pentagon-q[1].png pentagon-r[1].png
Geometry with the Discrete Fourier Transform

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